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MYSQL查询时间数据

时间:2024/3/22作者:未知来源:盘绰网教程人气:


[摘要]利用mysql查询时间数据在平常使用php中经常会遇到,本篇将介绍多种时间数据的查询。mysql查询本季度今天select * from 表名 where to_days(时间字段名) = to_d...
利用mysql查询时间数据在平常使用php中经常会遇到,本篇将介绍多种时间数据的查询。

mysql查询本季度

今天

select * from 表名 where to_days(时间字段名) = to_days(now());

昨天

SELECT *FROM表名WHERE TO_DAYS( NOW( ) ) – TO_DAYS( 时间字段名) <= 1

7天

SELECT *FROM表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名)

近30天

SELECT *FROM表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(时间字段名)

本月

SELECT *FROM表名 WHERE DATE_FORMAT( 时间字段名, ‘%Y%m’ ) = DATE_FORMAT( CURDATE( ) , ‘%Y%m’ )

上一月

SELECT *FROM表名 WHERE PERIOD_DIFF( date_format( now( ) , ‘%Y%m’ ) , date_format( 时间字段名, ‘%Y%m’ ) ) =1
#查询本季度数据 select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now()); #查询上季度数据 select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER)); #查询本年数据 select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW()); #查询上年数据 select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));
查询当前这周的数据 SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,’%Y-%m-%d’)) = YEARWEEK(now());
查询上周的数据 SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,’%Y-%m-%d’)) = YEARWEEK(now())-1;
查询当前月份的数据 select name,submittime from enterprisewhere date_format(submittime,’%Y-%m’)=date_format(now(),’%Y-%m’)
查询距离当前现在6个月的数据 select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();
查询上个月的数据 select name,submittime from enterprisewhere date_format(submittime,’%Y-%m’)=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),’%Y-%m’)
select*from`user`whereDATE_FORMAT(pudate,‘%Y%m‘)=DATE_FORMAT(CURDATE(),‘%Y%m‘) ; select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,’%y-%m-%d’)) = WEEKOFYEAR(now())
select* fromuser whereMONTH(FROM_UNIXTIME(pudate,‘%y-%m-%d‘))=MONTH(now())
select* from[user] whereYEAR(FROM_UNIXTIME(pudate,‘%y-%m-%d‘))=YEAR(now()) andMONTH(FROM_UNIXTIME(pudate,‘%y-%m-%d‘))=MONTH(now())
select* from[user] wherepudatebetween上月最后一天 and下月第一天
wheredate(regdate)=curdate();
select*fromtestwhereyear(regdate)=year(now())andmonth(regdate)=month(now())andday(regdate)=day(now())
SELECT date( c_instime ) ,curdate( )FROM `t_score`WHERE 1LIMIT 0 , 30

本文介绍了多个常用到的时间数据,更多相关内容请关注php中文网。

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